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Multiple States XI

Description

A sequence of numbers is called a wiggle sequence if the differences between successive numbers strictly alternate between positive and negative. The first difference (if one exists) may be either positive or negative. A sequence with fewer than two elements is trivially a wiggle sequence.

For example, [1,7,4,9,2,5] is a wiggle sequence because the differences (6,-3,5,-7,3) are alternately positive and negative. In contrast, [1,4,7,2,5] and [1,7,4,5,5] are not wiggle sequences, the first because its first two differences are positive and the second because its last difference is zero.

Given a sequence of integers, return the length of the longest subsequence that is a wiggle sequence. A subsequence is obtained by deleting some number of elements (eventually, also zero) from the original sequence, leaving the remaining elements in their original order.

https://leetcode.com/problems/wiggle-subsequence/description/

Example I

Input: [1,7,4,9,2,5]
Output: 6
Explanation: The entire sequence is a wiggle sequence.

Example II

Input: [1,2,3,4,5,6,7,8,9]
Output: 2

Example III

Input: [1,17,5,10,13,15,10,5,16,8]
Output: 7
Explanation: There are several subsequences that achieve this length. One is [1,17,10,13,10,16,8].

Questions

Transform Function

for(int i = 1; i < n; i++) {
    if(nums[i] > nums[i - 1]) {
        up[i] = down[i - 1] + 1;
        down[i] = down[i - 1];
    }else if(nums[i] == nums[i - 1]){
        down[i] = down[i - 1];
        up[i] = up[i - 1];
    }else{
        down[i] = up[i - 1] + 1;
        up[i] = up[i - 1];
    }
}

Solution I

class Solution {
    public int wiggleMaxLength(int[] nums) {
        if(nums == null || nums.length == 0) return 0;
        int n = nums.length;
        int[] up = new int[n];
        int[] down = new int[n];
        up[0] = 1;
        down[0] = 1;
        for(int i = 1; i < n; i++) {
            if(nums[i] > nums[i - 1]) {
                up[i] = down[i - 1] + 1;
                down[i] = down[i - 1];
            }else if(nums[i] == nums[i - 1]){
                down[i] = down[i - 1];
                up[i] = up[i - 1];
            }else{
                down[i] = up[i - 1] + 1;
                up[i] = up[i - 1];
            }
        }
        return Math.max(down[n - 1], up[n - 1]);
    }
}